[slurm-users] Error in job_submit.lua conditional?

[mercan]

Hi;

I think dirty debugging is required using printf (slurm.log_user), 
because the lua of our slurm installation returns a lot of variables as 
nil. You can limit the output to a specific user as below:

if job_desc.user_name == "mercan" then

     slurm.log_user("job_desc.user_id=")
     slurm.log_user(job_desc.user_id)
     slurm.log_user("job_desc.partition=")
     slurm.log_user(job_desc.partition)
end

Ahmet M.


On 5.02.2019 01:27, Prentice Bisbal wrote:
> Can anyone see an error in this conditional in my job_submit.lua?
>
>     if ( job_desc.user_id == 28922 or job_desc.user_id == 41266 ) and 
> ( job_desc.partition == 'general' or job_desc.partition == 
> 'interruptible' ) then
>         job_desc.qos = job_desc.partition
>         return slurm.SUCCESS
>     end
>
> I am one if those user id's but if I submit a job to partition 
> 'interruptible', without specifying a QOS, it still gets assigned to 
> the default QOS, which is 'general':
>
>  cat mpihello.sbatch
> #!/bin/bash
>
> #SBATCH -n 32
> #SBATCH -p interruptible
> #SBATCH -t 00:01:00
> #SBATCH -J mpihello
> #SBATCH -o mpihello-%j.out
> #SBATCH -e mpihello-%j.err
> #SBATCH --mail-type=ALL
>
> module load gcc/7.3.0
> module load openmpi/3.0.0
> srun --mpi=pmi2 ./mpihello
>
> $ scontrol show job 433953 | grep QOS
>    Priority=2512 Nice=0 Account=unix QOS=general
>
> The logic of that conditional seems pretty simple, and I'm using 
> similar compound conditionals throughout my job_submit.lua script. 
> Can't figure out where the mistake is in this one.
>