[slurm-users] Error in job_submit.lua conditional?

[Marcus Wagner]

Hi Prentice,


I also hate lua sometimes, as it does not complain, when you hope it 
would complain.

It is called 'userid', not 'user_id', so the first part is all the time 
false ;)


Best
Marcus


On 2/4/19 11:27 PM, Prentice Bisbal wrote:
> Can anyone see an error in this conditional in my job_submit.lua?
>
>     if ( job_desc.user_id == 28922 or job_desc.user_id == 41266 ) and 
> ( job_desc.partition == 'general' or job_desc.partition == 
> 'interruptible' ) then
>         job_desc.qos = job_desc.partition
>         return slurm.SUCCESS
>     end
>
> I am one if those user id's but if I submit a job to partition 
> 'interruptible', without specifying a QOS, it still gets assigned to 
> the default QOS, which is 'general':
>
>  cat mpihello.sbatch
> #!/bin/bash
>
> #SBATCH -n 32
> #SBATCH -p interruptible
> #SBATCH -t 00:01:00
> #SBATCH -J mpihello
> #SBATCH -o mpihello-%j.out
> #SBATCH -e mpihello-%j.err
> #SBATCH --mail-type=ALL
>
> module load gcc/7.3.0
> module load openmpi/3.0.0
> srun --mpi=pmi2 ./mpihello
>
> $ scontrol show job 433953 | grep QOS
>    Priority=2512 Nice=0 Account=unix QOS=general
>
> The logic of that conditional seems pretty simple, and I'm using 
> similar compound conditionals throughout my job_submit.lua script. 
> Can't figure out where the mistake is in this one.
>

-- 
Marcus Wagner, Dipl.-Inf.

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