[slurm-users] Simple script to identify inefficient

[Lachlan Musicman]

Works fine on CentOS 7.4

Some of my users are getting > 100% efficiency? That seems weird, tbh, but
I've not done a thorough analysis of their work/sbatch files.

L.

------
"The antidote to apocalypticism is *apocalyptic civics*. Apocalyptic civics
is the insistence that we cannot ignore the truth, nor should we panic
about it. It is a shared consciousness that our institutions have failed
and our ecosystem is collapsing, yet we are still here — and we are
creative agents who can shape our destinies. Apocalyptic civics is the
conviction that the only way out is through, and the only way through is
together. "

*Greg Bloom* @greggish
https://twitter.com/greggish/status/873177525903609857

On 18 November 2017 at 11:44, Chris Samuel <samuel at unimelb.edu.au> wrote:

> On Saturday, 18 November 2017 12:16:03 AM AEDT Sternberger, Sven wrote:
>
> > # ./wasteReport.py --partition --start "11/01-00:00" --order Efficiency
>
> Interesting, but just a heads up that it doesn't work on RHEL6.
>
> # ./wasteReport.py --partition --start "11/01-00:00" --order Efficiency
> Traceback (most recent call last):
>   File "./wasteReport.py", line 98, in <module>
>     cmdList.append("--starttime={}".format(args.starttime))
> ValueError: zero length field name in format
>
> I had to use one of our compiled 2.7.x versions of Python to get past that.
>
> All the best,
> Chris
> --
>  Christopher Samuel        Senior Systems Administrator
>  Melbourne Bioinformatics - The University of Melbourne
>  Email: samuel at unimelb.edu.au Phone: +61 (0)3 903 55545
>
>
>
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